in the following Python scripting:
op(‘serial1’).send(‘s2,2000,3\r’)
What is the syntax for replacing value ‘2000’ with a chop channel value ?
in the following Python scripting:
op(‘serial1’).send(‘s2,2000,3\r’)
What is the syntax for replacing value ‘2000’ with a chop channel value ?
assuming that it’s going to be an integer value (“2000” instead of “2000.0”), it’d be this:
op('serial1').send('s2,%d,3\r' % int(op("thechop")["somechannel"][0]))
thanks! works a charm. I think I understand all the code, except for the [0] at the end. Is that an initializing, arbitrary value for the chop chan ?
CHOP channels are indexed, and the index starts at zero. So when you call
op('constant1')[0]
You’re calling operator named constant1, and the first channel, which is index 0. If it was
op('constant1')[2]
It would grab the 3rd channel in the constant.
In my example, the [0] selects the first sample out the channel named “somechannel”. Each channel in a CHOP is effectively an array of values (even if it’s just an array that has 1 value in it), so this grabs the first of those values:
op("thechop")["somechannel"][0]
and this grabs the second sample from that same channel:
op("thechop")["somechannel"][1]
got it!. I knew that but forgot.
“repetition teaches” - Netochka Nezvanova/nato.0+55